The following sections cover several aspects of
Bridge
probabilities and combinatorics. Each section has a link that gives the
statistical results and another link that shows how the results are
calculated. The "How to" sections give both a generalized description
of the calculations and algorithm as well as the "C" source code.
Math
Symbols/Notation: Use this link for
explanations of
the math symbols used. Generally, we will use math notation as
expressed/used in Microsoft's Excel spreadsheets.
Bidding Combinatorics:
Statistics
"How
to"
calculations There are 1.28746 E+47 (Scientific
notation for
128+ billion billion billion billion billion (American billion =
1,000,000,000)) different ways to bid after the cards have been dealt.
Most of these sequences are nonsensical, but they are legal, hence they
must be counted. This is about 2.4 billion billion times larger than
the number of ways that four hands can be dealt from a deck of cards.
(Total number of possible deals = FACT(52) / ((FACT(13)^4) = 5.36447
E+28) (Note: The order of the cards in a bridge hand is not relevant.)
Bidding combinatorics for a hand is divided into 3
parts.
Part one is just 0 to 3 "Passes" before someone mentions a quantity (1
- 7) and a suit (or No Trump). Part 2 contains all quantity and suit
bids (We will count suit bids for the stats output) through the last
"quantity-suit" bid. This will include all possible intervening bids of
"pass", "double", and "redouble". Part 3 comes after the last
"quantity-suit" bid, and the only words allowed are "pass", "double",
and "redouble".
Suit Distribution Combinatorics:
Statistics
"How
to"
calculations It would be nice to be dealt all 13 cards of a
suit,
but it hasn't happened to me yet. (In practice, if I bid 7 "whatevers",
the next person would steal the hand with a bid of 7 No Trump. Worse
yet they would know the distribution and just might make it.)
The
most common suit distribution is 4, 4, 3, 2 and the mundane 4, 3, 3, 3
is actually only the 5th most common.
Point Count Combinatorics:
Statistics
"How
to"
calculations A guide to the strength of any given
hand is
frequently determined by the "Old reliable" point count. Using this
analysis, a player counts 4 points for every Ace in his hand, 3 points
for Kings, 2 points for Queens, and 1 point for Jacks. The total
becomes the point count. A hand that has no honors (not even a 10) is
frequently referred to as a "Yarborough" (9 high or worse). There are
347,373,600 "Yarboroughs" (COMBIN(32, 13)), and I think I'm already
working on the second half.
"With 8 ever, with 9 never" - Splits in
general:
Statistics
"How
to"
calculations This old rule of thumb is used to
determine
whether you should take a finesse or play for the drop given that you
have 8 or 9 cards in a suit (your hand plus the dummy), but are missing
the Queen. The statistical difference is quite small for the "With 9
never" portion, and is usually far outweighed by knowledge gained from
bidding, card play, or just plain keeping the dangerous opponent from
leading through your broken strength in other suits. Nevertheless we
will give the numbers, and you as a player can see things in
perspective.
Solutions to the round-robin Bridge
tournament problem (Whist Tournament Schedules)
http://www.durangobill.com/BridgeCyclicSolutions.html
Cyclic solutions for (4, 5, 8, 9, 12, 13, 16, 17, 20, 21, 24, 25, 28,
29, 32, 33, 36, 37, 40, 41, 44, 45, 48, 49, 52, 53, 56, 57, 60, 61, 64,
65, 68, 69, 72, 73, 76, 77, 80, 81, 84, 85, 88, 92, 96 players) up to
24 Bridge tables such that
each player has each other player as a partner once, and as an opponent
twice.
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